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81p^2-3=78
We move all terms to the left:
81p^2-3-(78)=0
We add all the numbers together, and all the variables
81p^2-81=0
a = 81; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·81·(-81)
Δ = 26244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{26244}=162$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-162}{2*81}=\frac{-162}{162} =-1 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+162}{2*81}=\frac{162}{162} =1 $
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